The DCET cutoff for Cf Cs(artificial Intel.) at KLE Technological University(Formerly BVBCET) Dharward Dist was 11,949 in 2024 (Round 2). Compare all rounds & years.
Based on 2024 data, you need a rank of 11,949 or better in Round 1. The final Round 2 cutoff was 11,949, meaning students with ranks up to 11,949 were admitted by the end of counseling.
KCET cutoffs vary annually based on candidate preferences and seat matrix. If your rank is close to 11,949, you should definitely include KLE Technological University(Formerly BVBCET) Dharward Dist in your option entry list during counseling.
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